from dontblink@feddit.it to rust@lemmy.ml on 12 Jan 20:00
https://feddit.it/post/13960933
This is what I’ve found:
In C and C++, two different operators are used for calling methods: you use . if you’re calling a method on the object directly and -> if you’re calling the method on a pointer to the object and need to dereference the pointer first. In other words, if object is a pointer, object->something() is similar to (*object).something().
What about Rust?
Rust doesn’t have an equivalent to the -> operator. Instead, Rust has what is called automatic referencing and dereferencing.
In other words, the following are the same:
p1.distance(&p2); (&p1).distance(&p2); Note: this automatic referencing behavior works because methods have a clear receiver-the type of self. Given the receiver and name of a method, Rust can figure out definitively whether the method is reading (&self), mutating (&mut self), or consuming (self).
I am not sureI understood the note correctly, what does it mean that there is a clear receiver? Also, doesn’t Rust actually have an operator for dereferencing (*) as well？
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